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📅 May 18, 2026 👤 scraface

May 18, 2026

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Contradiction: $a + d = 5$ and $a + d = 7$ cannot both hold. Thus, no...
But perhaps the problem meant the first term is $a$, third term is $a...
From $a + d = 5$, $a = 5 - d$. Substitute into $a + (a + 2d) = 14$:
$(5 - d) + (5 - d + 2d) = 14$ → $5 - d + 5 + d = 10 = 14$ → $10 = 14$,...
Hence, no such sequence exists.
Final answer: $\boxed{\text{No such sequence exists}}$
Question: Factor the expression $12x^3 - 18x^2 + 6x$ completely.
Solution: Factor out the greatest common factor, $6x$:
12x^3 - 18x^2 + 6x = 6x(2x^2 - 3x + 1)
Now factor the quadratic: $2x^2 - 3x

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