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Home » Game Awards 2024: The Biggest Surprises &惊天消息 You Need to See Now! - ClickBalance

Game Awards 2024: The Biggest Surprises &惊天消息 You Need to See Now! - ClickBalance

📅 May 19, 2026 👤 scraface

May 19, 2026

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📌 Solution: Let $ \mathbf{a} = \langle 1, 2, 3 \rangle $, $ \mathbf{b} = \langle 1, -2, 1 \rangle $. We are to find $ \mathbf{v} $ such that:

📌 \mathbf{v} \times \mathbf{a} = \mathbf{b}, \quad \mathbf{v} \cdot \mathbf{a} = 0

📌 We use the vector triple product identity. From $ \mathbf{v} \times \mathbf{a} = \mathbf{b} $, taking the cross product with $ \mathbf{a} $ on both sides:

📌 \mathbf{a} \times (\mathbf{v} \times \mathbf{a}) = \mathbf{a} \times \mathbf{b}

📌 Using the identity $ \mathbf{a} \times (\mathbf{v} \times \mathbf{a}) = (\mathbf{a} \cdot \mathbf{a})\mathbf{v} - (\mathbf{a} \cdot \mathbf{v})\mathbf{a} $, and since $ \mathbf{a} \cdot \mathbf{v} = 0 $, this becomes:

📌 \|\mathbf{a}\|^2 \mathbf{v} = \mathbf{a} \times \mathbf{b}

📌 Compute $ \|\mathbf{a}\|^2 = 1^2 + 2^2 + 3^2 = 1 + 4 + 9 = 14 $

📌 Now compute $ \mathbf{a} \times \mathbf{b} $:

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