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📰 We now find the maximum of $f(u)$ on this interval. Note that as $u \to 0^+$, $f(u) \to \infty$, but we must check whether a maximum occurs within the interval or at an endpoint. However, since all terms grow unbounded as $u \to 0$, but we must evaluate whether a minimum exists and whether the expression becomes large — yet we seek the **maximum**, which may occur near $u \to 0$, but let’s analyze behavior.
📰 But wait: as $u \to 0^+$, $\frac{1}{u^2} \to \infty$, so $f(u) \to \infty$. However, is this possible?
📰 Let’s test at $x = \frac{\pi}{4}$: $\sin x = \cos x = \frac{\sqrt{2}}{2}$, so $u = \frac{1}{2} \cdot \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{2}}{2} = \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{2}$
