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📅 May 18, 2026 👤 scraface

May 18, 2026

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🔥 Popular Posts

To find when \(C(t) = \frac{kt}{t^2 + 1}\) is maximized, find the crit...
First, compute the derivative using the quotient rule:
\[ C(t) = \frac{kt}{t^2 + 1} \]
If \(u = kt\) and \(v = t^2 + 1\), then
\[ u' = k, \quad v' = 2t \]
\[ C'(t) = \frac{(k)(t^2 + 1) - (kt)(2t)}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{k(t^2 + 1) - 2kt^2}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{kt^2 + k - 2kt^2}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{-kt^2 + k}{(t^2 + 1)^2} \]
\[ C'(t) = \frac{k(1 - t^2)}{(t^2 + 1)^2} \]

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