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Home » Now substitute \( b = \frac32 \) back into \( a = 2b - 1 \): - ClickBalance

Now substitute \( b = \frac32 \) back into \( a = 2b - 1 \): - ClickBalance

📅 May 18, 2026 👤 scraface

May 18, 2026

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📌 Since \( 32 = 2^5 \), we have \( 2^{x+1} = 2^5 \).

📌 So \( x + 1 = 5 \), and \( x = 4 \).

📌 The sum of two numbers is 20, and their product is 96. What is the larger number?

📌 Let the numbers be \( x \) and \( 20 - x \).

📌 Then \( x(20 - x) = 96 \).

📌 \( 20x - x^2 = 96 \) → \( x^2 - 20x + 96 = 0 \).

📌 Factoring: \( (x - 12)(x - 8) = 0 \) → \( x = 12 \) or \( x = 8 \).

📌 The larger number is 12.

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