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📅 May 19, 2026 👤 scraface

May 19, 2026

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\phi = 30^\circ + 360^\circ k \quad \text{or} \quad \phi = 330^\circ +...
Since $ \phi = 3\theta $, we substitute:
3\theta = 30^\circ + 360^\circ k \quad \Rightarrow \quad \theta = 10^\...
3\theta = 330^\circ + 360^\circ k \quad \Rightarrow \quad \theta = 110...
We now find all $ \theta \in [0^\circ, 360^\circ] $ by plugging intege...
For $ \theta = 10^\circ + 120^\circ k $:
$ k = 0 $: $ 10^\circ $
$ k = 1 $: $ 130^\circ $
$ k = 2 $: $ 250^\circ $
$ k = 3 $: $ 370^\circ $ → too large

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