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Home » Thus, the intersection point is \( \left(\frac43, \frac173\right) \). - ClickBalance

Thus, the intersection point is \( \left(\frac43, \frac173\right) \). - ClickBalance

📅 May 18, 2026 👤 scraface

May 18, 2026

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2a + 2b = (3 + \sqrt{5})a - (3 + \sqrt{5})b
2a - (3 + \sqrt{5})a + 2b + (3 + \sqrt{5})b = 0
\Rightarrow a(-1 - \sqrt{5}) + b(5 + \sqrt{5}) = 0
Solve for \( rac{a}{b} \):
a b ( -\overline{1 + \sqrt{5}} + (5 + \sqrt{5}) ) = 0 \Rightarrow -ra...
Let \( r = rac{a}{b} = rac{2x}{y} \), then:
r - \sqrt{5} r + 5 + \sqrt{5} = 0 \Rightarrow r(-1 - \sqrt{5}) = - (5...
\Rightarrow r = rac{5 + \sqrt{5}}{1 + \sqrt{5}}
r = rac{5 + \sqrt{5}}{1 + \sqrt{5}} \cdot rac{1 - \sqrt{5}}{1 - \sqr...
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